Exploring Leetcode 90: Mastering the Subset II Challenge
BTech CSE student at IIIT Ranchi | Aspiring Software Engineer | Passionate about coding, building innovative projects, and solving real-world problems through technology. Currently diving into web development, Machine learning and deep learning. Always learning, creating, and pushing boundaries! #Tech #Coding
On leetcode platform we have to solve for an integer array with the same logic and here we understand this problem using a string..
In this article, we delve into the intricacies of Leetcode's Subset II problem, a popular challenge that tests your ability to generate all possible subsets of a given set of numbers, including handling duplicates. We'll break down the problem, explore efficient strategies, and provide insights to help you master this challenge.
//wap to store all the subsets of a string with duplicate elements..
#include<bits/stdc++.h>
using namespace std;
void storeSubsets(string ans,string str,vector<string>& v,bool flag){
if(str.size()==0){
v.push_back(ans);
return;
}
char ch = str[0];
if(str.size()==1){
if(flag==true) storeSubsets(ans+ch,str.substr(1),v,true);
storeSubsets(ans,str.substr(1),v,true);
return;
}
char dh = str[1];
if(ch==dh){
if(flag==true) storeSubsets(ans+ch,str.substr(1),v,true);
storeSubsets(ans,str.substr(1),v,false);
}
else{
if(flag==true) storeSubsets(ans+ch,str.substr(1),v,true);
storeSubsets(ans,str.substr(1),v,true);
}
}
int main()
{
string str;
cout<<"Enter the input string : ";
getline(cin,str);
sort(str.begin(),str.end());
vector<string> v; //stores all the subsets..
storeSubsets("",str,v,true);
for(int i=0;i<v.size();i++){
cout<<v[i]<<endl;
}
return 0;
}
In conclusion, mastering the Subset II challenge on Leetcode requires a deep understanding of how to generate all possible subsets of a given set of numbers, especially when duplicates are involved. By breaking down the problem and exploring efficient strategies, you can enhance your problem-solving skills and tackle similar challenges with confidence. With practice and persistence, you'll be well-equipped to handle this and other complex algorithmic problems.
